Asked by Ken
A blood serum sample containing Na+ gave an emission signal of 4.27 mV. A small volume of concentrated standard Na+ was then added to increase the Na+ concentration by 0.102 M, without significantly diluting the sample. This "spiked" serum sample gave a signal of 8.09 mV. Find the original concentration of Na+ in the serum.
Answer is suppose to be 0.117 but I'm just not getting those numbers.
Answer is suppose to be 0.117 but I'm just not getting those numbers.
Answers
Answered by
DrBob222
0.102M is responsible for 8.09-4.27 = 3.82 mv.
Then 0.102 x (4.27/3.82) = 0.114M
Then 0.102 x (4.27/3.82) = 0.114M
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