Asked by vanessa
tiger woods hits tees off with an initial velocity of 80m/s at an angle of 23 degrees what will be the max height of his golf ball?how far will the golf ball travel
Answers
Answered by
Damon
Vi = 80 sin 23
v = Vi - 9.8 t = 80 sin 23 - 9.8 t
at top, v = 0
9.8 t = 80 sin 23
solve for t at top
now
h = Vi t - 4.9 t^2solve for h or alternatively
average speed up = Vi/2
h = (Vi/2)t
total time in air = 2 t
horizontal speed is constant = 80 cos23
so horizontal distance = 2t* 80 cos 23
v = Vi - 9.8 t = 80 sin 23 - 9.8 t
at top, v = 0
9.8 t = 80 sin 23
solve for t at top
now
h = Vi t - 4.9 t^2solve for h or alternatively
average speed up = Vi/2
h = (Vi/2)t
total time in air = 2 t
horizontal speed is constant = 80 cos23
so horizontal distance = 2t* 80 cos 23
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