Question

air has an average molar mass of 29.o g/mol. The density of air at 0.97 atm and 30. C is

Answer 1

D=[mol.wt*P)/(R*T)
D=(29.0 g/mol*0.97atm)/[(0.0821 atm*L/mol*K)*(303.15 K)]
=1.13 g/L

Answer 2

1.13

Answer 3

1st:273+30=303
2nd: (29 time .97) divid(.08205746time303)=1.131381296gper Liter is your answer