Asked by Keenia
Find the exact value of the trigonometric function. -cot(pi/4 + 16pi)
Answers
Answered by
Reiny
16π is the same as exactly 8 rotations, so
-cot(π/4 + 16π) = -cot(π/4)
= -1/tan(π/4) = -1/1 = -1
-cot(π/4 + 16π) = -cot(π/4)
= -1/tan(π/4) = -1/1 = -1
Answered by
Anonymous
cot ( A + B ) = 1 / tan ( A + B )
tan ( A + B )= ( tanA + tanB )/( 1 - tanA * tanB )
In this case:
A = pi / 4
B = 16 pi
tan ( pi / 4 ) = tan 45° = 1
tan ( 16 pi )= cot ( 8 * 2 pi ) = tan ( 8 * 360° ) = 0
tan ( pi / 4 + 16 pi ) =
[ ( tan ( pi / 4 ) + tan ( 16 pi ) ]/[ 1 - tan( pi / 4 ) * tan ( 16 pi ) ] =
( 1 + 0 ) / ( 1 - 1 * 0 ) =
1 / ( 1 - 0 ) =
1 / 1 = 1
tan ( pi / 4 + 16 pi ) = 1
cot ( pi / 4 + 16 pi ) =
1 / tan ( pi / 4 + 16 pi ) =
1 / 1 = 1
- cot ( pi / 4 + 16 pi ) = - 1
tan ( A + B )= ( tanA + tanB )/( 1 - tanA * tanB )
In this case:
A = pi / 4
B = 16 pi
tan ( pi / 4 ) = tan 45° = 1
tan ( 16 pi )= cot ( 8 * 2 pi ) = tan ( 8 * 360° ) = 0
tan ( pi / 4 + 16 pi ) =
[ ( tan ( pi / 4 ) + tan ( 16 pi ) ]/[ 1 - tan( pi / 4 ) * tan ( 16 pi ) ] =
( 1 + 0 ) / ( 1 - 1 * 0 ) =
1 / ( 1 - 0 ) =
1 / 1 = 1
tan ( pi / 4 + 16 pi ) = 1
cot ( pi / 4 + 16 pi ) =
1 / tan ( pi / 4 + 16 pi ) =
1 / 1 = 1
- cot ( pi / 4 + 16 pi ) = - 1
Answered by
Anonymous
tan ( 16 pi )= tan ( 8 * 2 pi ) = tan ( 8 * 360° ) = 0
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