Question

the chemistry question:

v=0.465L
T=559.15K
P=112.496 kPa

Pv/t = Pv/t

112.kpa(0.465)/559.15 = (x)(0.464428)/(247.8)

x= 49.9 kPa


...i skipped conversion steps, but i'm pretty sure i did those right..

Answer 1

The largest error I see is the 237.8 for T2 and I can't figures how you obtained that value. The problem states that the temperature is colled by 38.3 C (not to that temperature); therefore, T2 is 559.15-38.3 = 520.85. That gets a value CLOSE to 105 (104.45 using your numbers in the last line). I would have used 101.325 for the conversions. In fact, I wouldn't have converted all those numbers but once. Try this.
P1V2/T1= P2V2/T2
844*465/559.15 = P2*464.428/520.85
P2 = 787.408 torr
(787.408/760)*101.325 = 104.979 which rounds to 105 kPa.

Answer 2

i had to convert 38.3 to kelvin... because i converted the initial T to kelvin.

Answer 3

Yes, but 273.15 - 38.3 = 234.85 K which isn't your 247 something. .
What you want is 559.15 K, the initial termperature, minus 38.3 (it is coled by that amount) = 520.85 K for T2.

Answer 4

thank you so much for your help, i know it wasn't that difficult, i think i just confused myself with the temperatures. i get the answer now.

Answer 5

You're welcome.