Asked by Anonymous
The mass of the Mars is about 0.11 the mass of the earth, its radius is 0.53 that of the earth, and the acceleration due to gravity at the earth's surface is 9.80 {\rm m}/{\rm s}^{2}.
Answers
Answered by
tchrwill
g = µ/r^2 gravity on the surface of Mars
µ = the gravitational constant of Mars
= GM where G = the universal gravitational constant and M = the planet mass
r = the radius of Mars = .53(6378)1000
= 3,380,340m
G = 6.67259x10^-11
M = .11(5.97424x10^24) = 6.571664x10^23
Therefore, the Martian surface gravity = ~3.83m/sec^2.
µ = the gravitational constant of Mars
= GM where G = the universal gravitational constant and M = the planet mass
r = the radius of Mars = .53(6378)1000
= 3,380,340m
G = 6.67259x10^-11
M = .11(5.97424x10^24) = 6.571664x10^23
Therefore, the Martian surface gravity = ~3.83m/sec^2.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.