Asked by Alicia
Find the 265th term of an arithmetic sequence whose second term is 5/8 and whose 9th term is 71/24 pls help asap
Answers
Answered by
Reiny
a+d = 5/8
a + 8d = 71/24
subtract
7d = 7/3
d = 1/3
then in a+d = 5/8
a = 5/8 - 1/3 = 7/24
term 265 = a + 264d
=7/24 + 264/3 = 2119/24
a + 8d = 71/24
subtract
7d = 7/3
d = 1/3
then in a+d = 5/8
a = 5/8 - 1/3 = 7/24
term 265 = a + 264d
=7/24 + 264/3 = 2119/24