Asked by HELP

A lump of clay with a mass of 5.0 ! 10-2 kg is thrown toward a wall with a velocity of 3.0 m/s. The
clay bounces off the wall with a velocity of #0.5 m/s. What is the impulse on the clay?

If the clay in the previous problem impacted the wall for 5.0 ms, what was the average force on the
clay?

Answers

Answered by drwls
Impulse equals momentum change
= 3.5 m/s*5*10^-2 kg = 0.175 kg m/s

Divide that by 0.005 s for the average force, in newtons.
Answered by madalyn
-0.16m/s
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