Question

A lump of clay with a mass of 5.0 ! 10-2 kg is thrown toward a wall with a velocity of 3.0 m/s. The
clay bounces off the wall with a velocity of #0.5 m/s. What is the impulse on the clay?

If the clay in the previous problem impacted the wall for 5.0 ms, what was the average force on the
clay?

Answer 1

Impulse equals momentum change
= 3.5 m/s*5*10^-2 kg = 0.175 kg m/s

Divide that by 0.005 s for the average force, in newtons.

Answer 2

-0.16m/s