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A lump of clay with a mass of 5.0 ! 10-2 kg is thrown toward a wall with a velocity of 3.0 m/s. The
clay bounces off the wall with a velocity of #0.5 m/s. What is the impulse on the clay?

If the clay in the previous problem impacted the wall for 5.0 ms, what was the average force on the
clay?
13 years ago

Answers

drwls
Impulse equals momentum change
= 3.5 m/s*5*10^-2 kg = 0.175 kg m/s

Divide that by 0.005 s for the average force, in newtons.
13 years ago
madalyn
-0.16m/s
11 years ago

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