Question

An airplane wing is designed so that the speed of the air across the top of the wing is 274 m/s when the speed of the air below the wing is 193 m/s. The density of the air is 1.29 kg/m3. What is the lifting force on a wing of area 25.0 m2?
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I know that it is the pressure difference times the area of the wing.

I know I need to use Bernoulli's equation but I do not know how incorporate area into it.

Answer 1

find the pressure difference between below and above with Bernoulli

multiply that pressure difference by 25 m^2 to get the force

Answer 2

P1 + 1/2 rho v1^2 = P2 + 1.2 rho v2^2

P1 -P2 = (1/2) rho (v2^2-v1^2)
= (1/2) (1.29)(274^2-193)^2

multiply that by 25

Answer 3

P1 -P2 = .5* (v1^2-v2^2)

difference in pressure multiplied by area