Asked by Anonymous
In circle O, diameter RS has endpoints R(3a,2b-1) and S(a-6,4b+5). Find the coordinates of point O in terms of a and b. Express your answer in simplest form.
Answers
Answered by
Steve
we know that the end points of a diameter have radially symmetric coordinates. so,
3a = -(a-6)
3a = -a + 6
4a = 6
a = 3/2
2b-1 = -(4b+5)
2b-1 = -4b-5
6b = -4
b = -2/3
R = (9/2,-7/3)
S = (-9/2,7/3)
3a = -(a-6)
3a = -a + 6
4a = 6
a = 3/2
2b-1 = -(4b+5)
2b-1 = -4b-5
6b = -4
b = -2/3
R = (9/2,-7/3)
S = (-9/2,7/3)
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