area of triangle XYZ

given:side z=11 side x=7 and side y=13
what are the angles and area please?
please explain

2 answers

If you are given all 3 sides, you must use the cosine law.
lets find ange Ø, where Ø is opposite the 13
(I always find the largest angle, because the calculator will give us the correct angle if the angle is obtuse)

13^2 = 11^2 + 7^2 - 2(11)(7)cosØ
154cosØ = 121 + 49 - 169
cosØ = 1/154 = .00649
Ø = 89.63°

You now could use the Sine Law to find a second angle
The third angle is then trivial.
could you elaborate?im kind of new to this.