Delta G = -RTLNK
For c6h6 (l) to c6h6 (g) equilibrium, delta G = 129.66-124.50 = 5.16 kJ/Mol
Plug this value into the equation above and solve for the value of K, which is simply the ratio of product to reactant.
Repeat this calculation for ccl4.
Reposting with correct information..Carbon tetrachloride (CCl4) and benzene (C6H6) form ideal solutions. Consider an equimolar solution of CCl4 and C6H6 at 25°C. The vapor above this solutionis collected and condensed. Using the following data, determine the composition in mole fraction of the condensed vapor.
Substance ∆Gf°
C6H6 (l) 124.50 kJ/mol
C6H6 (g) 129.66 kJ/mol
CCl4 (l) -65.21 kJ/mol
CCl4 (g) -60.59 kJ/mol
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