Asked by Someone12
A 17 kg child descends a slide 3.5 m high and reaches the bottom with a speed of 1.5 m/s. How much work was done by the friction as the child goes down the slide?
Answers
Answered by
Damon
Pe lost = m g h
Ke gained = (1/2) m v^2
Pe lost - Ke gained = energy lost to friction
Ke gained = (1/2) m v^2
Pe lost - Ke gained = energy lost to friction
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