Asked by Anonymous
circle
x^2+y^2-6x+12y+33=0
1. transform equation to standard form
2. graph
3. label centers
4. mark radius of each
x^2+y^2-6x+12y+33=0
1. transform equation to standard form
2. graph
3. label centers
4. mark radius of each
Answers
Answered by
Reiny
complete the square
x2 - 6x + ..... + y^2 + 12y + .... = -33
x^2 - 6x + 9 + y^2 + 12y + 36 = -33 + 9 + 36
(x+3)^2 + (y+6)^2 = 12
I am sure you can finish the question from here,
but...
I am puzzles by 3. and 4.
it says to label centres and in 4. to mark the radius of each.
That suggests that there are more than one circle.
x2 - 6x + ..... + y^2 + 12y + .... = -33
x^2 - 6x + 9 + y^2 + 12y + 36 = -33 + 9 + 36
(x+3)^2 + (y+6)^2 = 12
I am sure you can finish the question from here,
but...
I am puzzles by 3. and 4.
it says to label centres and in 4. to mark the radius of each.
That suggests that there are more than one circle.
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