Question

A cue ball (mass = 0.140 kg) is at rest on a frictionless pool table. The ball is hit dead center by a pool stick which applies an impulse of +1.60 N·s to the ball. The ball then slides along the table and makes an elastic head-on collision with a second ball of equal mass that is initially at rest. Find the velocity of the second ball just after it is struck

Answer 1

impulse= mass x delta velocity

delta velocity = impulse/ mass

and since the equation is elastic meaning all force and momentum are always transferred in a direct collision, velocity from the initial ball will transfer too the second ball