Asked by sherman
Cos 3 alpha = - 0.1 solutions in degree
Answers
Answered by
Steve
what's the problem?
cos 3θ = -0.1
3θ = cos<su>-1</sup>(-.1)
3θ = 95.74°
θ = 31.91°
sorry about the θ -- didn't have an alpha handy.
cos 3θ = -0.1
3θ = cos<su>-1</sup>(-.1)
3θ = 95.74°
θ = 31.91°
sorry about the θ -- didn't have an alpha handy.
Answered by
Steve
oops
cos 3θ = -0.1
3θ = cos<sup>-1</sup>-.1
3θ = 95.74°
θ = 31.91°
cos 3θ = -0.1
3θ = cos<sup>-1</sup>-.1
3θ = 95.74°
θ = 31.91°
Answered by
Reiny
you know the cosine is negative in II and III
cos 84.26° = +.1
so 3 alpha = 180 -84.26 or 3alpha = 180+84.26
alpha = 31.9° or 88.1°
You did not state the domain of alpha, I will assume between 0 and 360°
period of cos 3alpha is 360°/3 = 120°
so adding 120 to any answer will yield a new answer
alpha = 31.9 +120 = 151.9
alpha = 151.9+10 = 271.9
alpha = 271.9+120 = 391.9 -- too big
alph = 88.1+120 = 208.1
alpha = 208.1+120 = 328.1
alpha = 31.9, 88.1, 151.9, 208.1, 271.9, and 328.1
cos 84.26° = +.1
so 3 alpha = 180 -84.26 or 3alpha = 180+84.26
alpha = 31.9° or 88.1°
You did not state the domain of alpha, I will assume between 0 and 360°
period of cos 3alpha is 360°/3 = 120°
so adding 120 to any answer will yield a new answer
alpha = 31.9 +120 = 151.9
alpha = 151.9+10 = 271.9
alpha = 271.9+120 = 391.9 -- too big
alph = 88.1+120 = 208.1
alpha = 208.1+120 = 328.1
alpha = 31.9, 88.1, 151.9, 208.1, 271.9, and 328.1
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