Asked by chrystabelle1
If y= e(power x) + e(power -x)/2 when y =1
Answers
Answered by
drwls
Do you want to know x when y is 1?
y never gets as low as 1, for any value of x.
When x = 0, y = 1.500
When x = -0.4, y = 1.4162
When x = -0.45, y = 1.4286
When x = -0.5, y = 1.4309
When x = -0.6, y = 1.4599
y never gets as low as 1, for any value of x.
When x = 0, y = 1.500
When x = -0.4, y = 1.4162
When x = -0.45, y = 1.4286
When x = -0.5, y = 1.4309
When x = -0.6, y = 1.4599
Answered by
Steve
However, knowing how loose folks are with parentheses around here, it's possible she meant
(e^x - e^(-x))/2 = sinh(x)
so,
e^x - e^-x = 2
e^x - 2 - e^-x = 0
clearing the fraction,
e^2x - 2e^x - 1 = 0
this is just a quadratic in e^x
e^x = (2 ± √8)/2
= 1 ± √2
e^x cannot be negative, so we have
e^x = 1 + √2
x = ln(1+√2) = 0.88137
check: asinh(1) = 0.88137
(e^x - e^(-x))/2 = sinh(x)
so,
e^x - e^-x = 2
e^x - 2 - e^-x = 0
clearing the fraction,
e^2x - 2e^x - 1 = 0
this is just a quadratic in e^x
e^x = (2 ± √8)/2
= 1 ± √2
e^x cannot be negative, so we have
e^x = 1 + √2
x = ln(1+√2) = 0.88137
check: asinh(1) = 0.88137
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