Asked by Beth
A cylindrical water tank has a radius of 2 feet and a height of 6.0 feet. Compute the work done to pump the water out of a filled tank through the top. [The density of water is 62.4 lbs/ft3.]
Answers
Answered by
MathMate
Height of tank=
H=6'
Total volume of water
V=πr²H
Total mass
m=ρV
Average height raised
h=H/2 (from centre of gravity to top)
Total work done
=mgh
g=acceleration due to gravity
=32.2 ft.s-2
Note:
If the water is supposed to load a truck below the tank, a pump is necessary to start filling the hose to the top and down, after that, water will flow up the tank, and down to the truck by gravity.
H=6'
Total volume of water
V=πr²H
Total mass
m=ρV
Average height raised
h=H/2 (from centre of gravity to top)
Total work done
=mgh
g=acceleration due to gravity
=32.2 ft.s-2
Note:
If the water is supposed to load a truck below the tank, a pump is necessary to start filling the hose to the top and down, after that, water will flow up the tank, and down to the truck by gravity.
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