Asked by Bree
Sec (23π/6)
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Answered by
MathMate
sec(23π/6)
=sec(23π/6 ± 2kπ) k integer
=sec(23π/6 - 24π/6)
=sec(-π/6)
=1/cos(π/6) (cos(-x)=cos(x), sec=1/cos)
=(2/3)√3
=sec(23π/6 ± 2kπ) k integer
=sec(23π/6 - 24π/6)
=sec(-π/6)
=1/cos(π/6) (cos(-x)=cos(x), sec=1/cos)
=(2/3)√3
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