Question

find d^2y/dx^2 of x^2/3 + y^2/3 =1
(implicit differentiation)

Answer 1

Differentiate both sides with respect to x, with y considered a function of x.

(2/3)/x^1/3 + [(2/3)/y^1/3] dy/dx = 0
dy/dx = -[y/x]^1/3

Then do it again.

d^2/dx^2 = .......