f= log3(u)
f'= 1/u * log3 e * u'
so here
f'=1/(x+x^2) * log3 e * (1+2x)
what is the derivative of log3(x+X^2)
log with base 3
i cant figure it out
1 answer
log with base 3
i cant figure it out
1 answer
1 answer
1 answer
2 answers
0 answers