Asked by Anonymous

A chemist dilutes 144.0 mL of 0.0743 M HCl with 775.0 mL of water. Determine the pH of the diluted solution.
1.86, 1.13, 2.08, 1.93, 12.07
Answered by DrBob222
moles HCl = M x L
New concn = moles/new L
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