Asked by Lindsay
On an air track, a 403.0 glider moving to the right at 2.30 collides elastically with a 501.0 glider moving in the opposite direction at 3.00 .Find the velocity of first glider after the collision
Answers
Answered by
Henry
Given:
M1 = 0.403kg, V1 = 2.30 m/s.
M2 = 0.501kg, V2 = -3.00 m/s.
V3 = (V1(M1-M2) + 2M2*V2)/(M1+M2).
V3 = (2.3(0.403-0.501)+1.002*(-3.0))/0.904 = -3.57 m/s = Velocity of M1 after collision.
V3 is moving to the left.
M1 = 0.403kg, V1 = 2.30 m/s.
M2 = 0.501kg, V2 = -3.00 m/s.
V3 = (V1(M1-M2) + 2M2*V2)/(M1+M2).
V3 = (2.3(0.403-0.501)+1.002*(-3.0))/0.904 = -3.57 m/s = Velocity of M1 after collision.
V3 is moving to the left.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.