Asked by Tim
Divers dive straight out from a cliff that is 21 m high. If the rocks below the cliff extend outward for 15 m, what is the minimum horizontal velocity a diver must have to clear the rocks safely
Answers
Answered by
Henry
h = Vo*t + 0.5g*t^2 = 21 m.
0 + 4.9t^2 = 21,
t^2 = 4.29,
t = Tf = 2.07s. = Fall time = Time in flight.
d = Vt,
V = d/t = 15 / 2.07 = 7.25m/s. = Hor.
velocity.
0 + 4.9t^2 = 21,
t^2 = 4.29,
t = Tf = 2.07s. = Fall time = Time in flight.
d = Vt,
V = d/t = 15 / 2.07 = 7.25m/s. = Hor.
velocity.
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