Asked by Kyle
A string vibrates according to the equation
y' = (0.30 cm) sin[(π/3 cm-1)x] cos[(55π s-1)t]
What is the speed of a particle of the string at the position x = 1.5 cm when t = 9/8 s?
y' = (0.30 cm) sin[(π/3 cm-1)x] cos[(55π s-1)t]
What is the speed of a particle of the string at the position x = 1.5 cm when t = 9/8 s?
Answers
Answered by
Damon
This is a standing wave.
y at constant x = 1.5
=.3 sin [1.5(pi/3-1)] cos t(55 pi -1)
so
dy/dt at constant x = 1.5
={.3 sin [1.5(pi/3-1)]} * {(1-55pi)sin [(9/8)55pi-1)] }
y at constant x = 1.5
=.3 sin [1.5(pi/3-1)] cos t(55 pi -1)
so
dy/dt at constant x = 1.5
={.3 sin [1.5(pi/3-1)]} * {(1-55pi)sin [(9/8)55pi-1)] }
Answered by
Kyle
I kinda wrote my equation wrong so heres a new version:
y' = (0.30 cm) sin[(π/3 cm^(-1))x] cos[(55πs^(-1))t]
y' = (0.30 cm) sin[(π/3 cm^(-1))x] cos[(55πs^(-1))t]
Answered by
Damon
I thought it was messed up. The method I gave you is how to go about it anyway.
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