heat gained by gold + heat lost by water = 0
[mass Au x specific heat Au x (Tfinal-Tinitial)] + [mass H2O x specific heat water x (Tfinal-Tinitial) = 0
Solve for Tfinal.
Note that you quote specific heat of Au and H2O in J/mol; therefore, the mass of Au and mass H2O must be in moles.
If a chalice made of pure gold weighing 1.24 kg and initially at 15 C is filled with 100.0 mL of water at 89 C, what is the final equilibrium temperature of the system? The heat capacities of water and gold are 75.29 and 25.42 J/mol/K, respectively.
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