Question

in march, the savings of oliver, asia, hassan, and abby was $1440. in april, their savings became equaly when oliver's savings is doubled, asia's savings is decreased by $30, abby's savings is increased by $46, and hassan remained the same. find the total saving in april.

Answer 1

in March, let their individual savings be
a, b, c, and d ---> a+b+c+d = 1440

in April,
Oliver: 2a
Asia: b-30
Hassan: c
Abby: d+46
total = 2a + b-30 + c + d+46
= a + b + c + d + a + 16
= 1440 + a + 16 = 1456 + a

also: 2a = b-30 = c = d+46

b -30= 2a , ---> b = 2a+30
c = 2a
d+46 = 2a ----> d = 2a-46


so in a+b+c+d=1440
a + 2a+30 + 2a + 2a-46 = 1440
7a = 1456
a = 208

total in April = 1456+a = 1456+208 = 1664

check:
a=208, b=446 , c = 416, d = 370
March: 208+446+416+370 = 1440
April: 416+416+416+416 = 1664

Answer 2

In April all their savings equal Hassan's.
a=oliver
b=aisa
h=hassan
d=abby

In april
a=h
b=h
h=h
d=h
So...
In March
h + 1/2h + h + 30 + h - 46 = 1440
In total: 7/2h - 16 = 1440
2/7 x 7/2h = 456 x 2/7
h = 416
So then multiply it by 4 and you get the amount saved in April.