To selectively precipitate either the silver ions or the strontium ions while leaving the other ion in solution, you can utilize different precipitation reactions. Here are three reaction plans for achieving this:
Reaction Plan 1: Precipitate Silver Ions
1. Add a few drops of dilute hydrochloric acid (HCl) to the mixture solution. Silver ions (Ag+) will react with chloride ions (Cl-) to form insoluble silver chloride (AgCl) precipitate.
Ag+ (aq) + Cl- (aq) → AgCl (s)
2. Filter the solution, separating the precipitated silver chloride (AgCl) from the remaining solution. The silver chloride is retained on the filter paper, while the strontium ions remain in the filtrate.
Reaction Plan 2: Precipitate Strontium Ions
1. Add a few drops of dilute sulfuric acid (H2SO4) to the mixture solution. Strontium ions (Sr2+) will react with sulfate ions (SO42-) to form insoluble strontium sulfate (SrSO4) precipitate.
Sr2+ (aq) + SO42- (aq) → SrSO4 (s)
2. Filter the solution, separating the precipitated strontium sulfate (SrSO4) from the remaining solution. The strontium sulfate is retained on the filter paper, while the silver ions remain in the filtrate.
Reaction Plan 3: Precipitate Silver Ions
1. Add a few drops of a sodium chloride (NaCl) solution to the mixture solution. Silver ions (Ag+) will react with chloride ions (Cl-) to form insoluble silver chloride (AgCl) precipitate.
Ag+ (aq) + Cl- (aq) → AgCl (s)
2. After the formation of silver chloride precipitate, add excess ammonia solution (NH3). Silver chloride dissolves in excess ammonia due to the formation of a soluble complex, called diamminesilver(I) complex.
AgCl (s) + 2NH3 (aq) → [Ag(NH3)2]+ (aq) + Cl- (aq)
3. Filter the solution to separate the retained silver chloride (AgCl) precipitate. The strontium ions remain in the filtrate.
In all three reaction plans, by selectively precipitating one ion, the other ion remains in the solution. The choice between the reaction plans can depend on the specific laboratory setup, available chemicals, or preferences.