CH4 + 2O2 ==> CO2 + 2H2O
Convert 20 L O2 to L CH4.
20 L CO2 x (1 mole CH4/2 moles O2) = 20 x (1/2) = 10 L CH4.
All volume measurements are carried out at the same temperature and pressure. If 20.0 L of O2 (g) are allowed to completely react with a sample of pure CH4 (g) in a combustion process producing CO2 (g) as the only carbon-containing product, what is the maximum volume of CH4 (g) that can be consumed in that reaction?
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