Ask a New Question

Question

A radio set at a sound level of 20 dB is suddenly increased to 80 dB. how many more time greater is the pressure amplitude at 80 dB? I do not know what to do please help
13 years ago

Answers

Henry
20Log(Vo/Vi) = 20db,
Log(Vo/Vi) = 1,
Vo/Vi = 10^1 = 10. = Voltage ratio.

20Log(Vo/Vi) = 80db,
Log(Vo/Vi) = 4,
Vo/Vi = 10^4 = 10,000.

Ratio = 10^4 / 10^1 = 10^3 = 1,000.

Therefore, the signal level at 80db is
1,000 times the signal level at 20db.
13 years ago

Related Questions

Calculate the sound level in decibels of a sound wave that has an intensity of 2.25 µW/m2. F Calculate the sound level in decibels of a sound wave that has an intensity of 2.25 µW/m2 For th... The sound level in decibles, B, can be found using the equation B=10 log(I/10^-12). what is the soun... why is sound important to radio The intensity level of a sound is reported in unit decibel(dB). how does IL change if we increase a... The sound level in decibels is typically expressed as β = 10 log (I/I0), but since sound is a pressu... If a sound's decibel level is extremely low, it can damage the listener's ears when it hits the eard... 14. The sound level in normal city traffic is approximately 85 dB. The sound level while riding a s... Radio waves Energy Level (Put either Lowest, Low, Highest, High/ Anything above 1015 for Hz is hi...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use