Asked by George
magnesium nitrate decompses in water and releases ammonia gas. If 355ml of ammonia is produced at STP, whit is the mass of Magnesim nitrate that reacted. Equation is Mg3N2+6H2O=3Mg(OH)2+2NH3
Answers
Answered by
DrBob222
You mean magnesium NITRIDE. Magnesium nitrate is Mg(NO3)2 and it does not produce NH3 when reacted with H2O.
Convert 355 mL NH3 to moles. moles = L/22.4 = ? moles NH3.
Convert moles NH3 to moles Mg3N2 using the coefficients in the balanced equation.
?moles NH3 x (1 mole Mg3N2/2 moles NH3) = ? moles Mg3N2.
Convert to grams. g = moles x molar mass.
Convert 355 mL NH3 to moles. moles = L/22.4 = ? moles NH3.
Convert moles NH3 to moles Mg3N2 using the coefficients in the balanced equation.
?moles NH3 x (1 mole Mg3N2/2 moles NH3) = ? moles Mg3N2.
Convert to grams. g = moles x molar mass.
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