Asked by darren

A 40.6-kg crate rests on a horizontal floor, and a 69.1-kg person is standing on the crate. Determine the magnitude of the normal force that (a) the floor exerts on the crate and (b) the crate exerts on the person.

Answers

Answered by Damon
total weight on floor = 9.8*(40.6+69.1) Newtonns which is the force up from the floor on the crate.
for the crate to the person, the person's weight which is 9.8*69.1 Newtons
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions