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FInd the area of the region between y=x^(1/2) and y=x^(1/5) for 0<x<1.

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∫x^1/5 - x^1/2 dx = 5/6 x^6/5 - 2/3 x^3/2[0,1]

= (5/6 - 2/3) - (0-0) = 1/6

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