Asked by bethel
Antiderivativeofe.5x-0.1x
Answers
Answered by
Steve
f'(x) = e^.5x - .1x
f(x) = (1/.5)e^.5x - .1(1/2)x^2
f(x) = 2e^.5x - .05x^2 + C
f(x) = (1/.5)e^.5x - .1(1/2)x^2
f(x) = 2e^.5x - .05x^2 + C
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