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a test has a mean score 73 with standard deviation of 12.students with scores greater than 85 receive an A. What is the percent of the students would we expect to get an A? assume the normal distribution
13 years ago

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PsyDAG
Z = (score-mean)/SD

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion related to the Z score.
13 years ago

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