Asked by Anonymous
How much work would be done if a 50 kg block was pulled horizantally at a 30 degree angle to the horizantal for 10 meters.
a) With zero friction
b) With -100N friction
a) With zero friction
b) With -100N friction
Answers
Answered by
Henry
Wb = mg = 50kg * 9.8N/kg = 490N. = Weight of block.
Fb = 490N @ odeg.
Fh=490sin(0) = 0 = Hor. force of block
Fv = 490cos(0) = 490N. = Force perpendicular to surface = Normal.
a. Fap*cos30 - Fh - Ff = 0,
Fap*cos30 - 0 - 0 = 0,
Fap*cos30 = 0,
Fap = 0 = Force applied.
Work = Fd = 0 * 10 = 0.
b. Fap*cos30 - 0 - 100 = 0,
Fap*cos30 = 100,
Fap = 100 / cos30 = 115.5N. = Force applied.
Work = Fd = 115.5cos30 * 10 = 1000J.
Fb = 490N @ odeg.
Fh=490sin(0) = 0 = Hor. force of block
Fv = 490cos(0) = 490N. = Force perpendicular to surface = Normal.
a. Fap*cos30 - Fh - Ff = 0,
Fap*cos30 - 0 - 0 = 0,
Fap*cos30 = 0,
Fap = 0 = Force applied.
Work = Fd = 0 * 10 = 0.
b. Fap*cos30 - 0 - 100 = 0,
Fap*cos30 = 100,
Fap = 100 / cos30 = 115.5N. = Force applied.
Work = Fd = 115.5cos30 * 10 = 1000J.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.