Asked by Scott
solve sin t= .6 on the interval 0<t<2pi
Answers
Answered by
Steve
t will be in the 1st or 2nd quadrant since sin t > 0
sin 36.9° = .6
so, in the 2nd quadrant,
sin 143.1° = .6
You can use radians if you want.
sin 36.9° = .6
so, in the 2nd quadrant,
sin 143.1° = .6
You can use radians if you want.
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