Asked by ceasar
Three points A,B and C have coordinates (1,0),(4,4) and (13,5) respectively.
1.By how many units does the length of AC exceed the length of AB
2.What is the slope of BC
1.By how many units does the length of AC exceed the length of AB
2.What is the slope of BC
Answers
Answered by
drwls
1. The length of AC is
sqrt[(13-1)^2 + (5-0)^2]
= sqrt169 = 13
The length of AB is
sqrt[(4-1)^2 + (4-0)^2]
= sqrt(25) = 5
The difference in lengths is 8.
2. BC slope = delty/deltax
= (5-4)/(13-4) = 1/9
sqrt[(13-1)^2 + (5-0)^2]
= sqrt169 = 13
The length of AB is
sqrt[(4-1)^2 + (4-0)^2]
= sqrt(25) = 5
The difference in lengths is 8.
2. BC slope = delty/deltax
= (5-4)/(13-4) = 1/9
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