if that is constant acceleration,
a = (v-u)/t
plug inthe numbers and you get the time elapsed.
how long does a car with an acceleration of 2.0 m/s^2 take to go from 10m/s to 30m/s?and its solution
2 answers
GIVEN:
Vf=30m/s
Vi=10m/s
a=.0m/s^2
REQUIRED:
t=?
SOLUTION
t=(Vf-Vi)/a
=(30m/s-10m/s)/2.0m/s^2
t=10s
Vf=30m/s
Vi=10m/s
a=.0m/s^2
REQUIRED:
t=?
SOLUTION
t=(Vf-Vi)/a
=(30m/s-10m/s)/2.0m/s^2
t=10s