A force vector points at an angle of 51.6 above the +x axis. It has a y component of +494 newtons (N). Find (a) the magnitude and (b) the the x component of the force vector.

Answer 1

Let the vector be V.

Vsin(51.6)= 494.

for the x-component,

V(x) = Vcos(51.6)

Try drawing the y,and x axis, the vector V, and a right angled triangle.

Answer 2

F sin 51.6 = 494
solve for F
Fx = F cos 51.6