Asked by Anonymous


A force vector points at an angle of 51.6 above the +x axis. It has a y component of +494 newtons (N). Find (a) the magnitude and (b) the the x component of the force vector.

Answers

Answered by Andrew
Let the vector be V.

Vsin(51.6)= 494.

for the x-component,

V(x) = Vcos(51.6)

Try drawing the y,and x axis, the vector V, and a right angled triangle.
Answered by Damon
F sin 51.6 = 494
solve for F
Fx = F cos 51.6
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