Asked by Lauren
A eudiometer contains 65.0 ml sample of gas collected by the diplacement of water. The water levels inside and outside the eudiometer are the same. The atmospheric pressure is 92.5 kPa and the temperture is 23 degrees. What volume will the dry gas occupy at STP? The vapor pressure of water at 23 degrees is 2.8 kPa.
92.5kPa-2.8kPa= 89.7kPa
65.0 ml(89.7 kPa)/101.3 kPa
answer: 57.6 ml
92.5kPa-2.8kPa= 89.7kPa
65.0 ml(89.7 kPa)/101.3 kPa
answer: 57.6 ml
Answers
Answered by
bobpursley
The only difficulty here is the temp. As I see it you correctly calcuated the volume at standard pressure, 23C. You need to adjust the volume for temperature now.
Answered by
Lauren
I think this might be right...adjusting the volume for temperature.
273K + 23K= 296K
The two possible temperature ratio would be 296K/273K or 273K/296K. I chose the second one.
57.6 ml(273K)/296K
answer: 53.1 ml
273K + 23K= 296K
The two possible temperature ratio would be 296K/273K or 273K/296K. I chose the second one.
57.6 ml(273K)/296K
answer: 53.1 ml
Answered by
DrBob222
That looks good to me.
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