One canned juice drink is 30% orange juice, another is 10% orange juice. How many liters of each should be mixed together in order to get 20L that is 18% orange juice?
2 answers
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oj in x liters of 30% = .3x
oj in (20-x) liters of 10% = .1(20-x)
oj in 20 liters of 18% = .18(20)
.3x + .1(20-x) = .18(20)
.3x + 2 - .1x = 3.6
.2x = 1.6
x = 8
so, 8L of 30% + 12L of 10% = 20L of 18%
8*.3 + 12*.1 = 2.4+1.2 = 3.6 = .18*20
oj in (20-x) liters of 10% = .1(20-x)
oj in 20 liters of 18% = .18(20)
.3x + .1(20-x) = .18(20)
.3x + 2 - .1x = 3.6
.2x = 1.6
x = 8
so, 8L of 30% + 12L of 10% = 20L of 18%
8*.3 + 12*.1 = 2.4+1.2 = 3.6 = .18*20