Asked by Kaleen

A 11.8 mL sample of a HCl solution has a pH of 2.000. What volume of water must be added to change the pH to 4.000?
Answered by DrBob222
pH = 2; convert to H^+ (which will be concn in moles/L = M). Convert pH 4 to H^+. Then
mL1 HCl x M1 HCl = mL2HCl x M2HCl
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