Asked by nelson
A surfer is catching a wave. Suppose she starts at the top of a wave with a speed of 1.37 m/s and moves down the wave until her speed increases to 9.90 m/s. The drop in her vertical height is 2.64 m. If her mass is 63.3 kg, how much work is done by the (nonconservative) force of the wave?
Answers
Answered by
drwls
Work done by the wave equals kinetic energy increase minus gravitational potential energy loss.
W = (M/2) (V2^2 - V1^)2 - M*g*deltaH
where deltaH = 1.27 m
W = (M/2) (V2^2 - V1^)2 - M*g*deltaH
where deltaH = 1.27 m
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