Question

. The number of vibrations per second made when a stretched wire is plucked varies directly as the square root of the tension in the wire and inversely as the length.

If a 1.23 m long wire will vibrate 325 times each second when the tension is 115 N, determine the number of vibrations per second if the wire is shortened to 0.95 m and the tension is decreased to 92.0 N.

Answer 1

frequency = k √t/L

given: 325 = k√115/1.23
k = 1.23(325)/√115

for 2nd case
frequency = (1.23(325)/√115) √92/.95
= .....

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