Ask a New Question

Question

A 2.0 nF parallel plate capacitor with a sheet of mylar (k= 3.1) filling the space between the plates is charged to a potential difference of 90 V and is them disconnected. How much work would be required to completely remove the sheet of mylar from the space between the two plates?
13 years ago

Answers

Related Questions

1) A parallel plate capacitor has a potential difference between its plates of 1.2 V and a plate sep... A 1.63 nF parallel-plate capacitor is charged to an initial potential difference ΔVi = 100 V and... A parallel plate capacitor is made of two 3.0 cm x 3.0 cm square plates that are separated by 1.0 mm... A parallel-plate capacitor is constructed from two circular metal plates or radius R. The plates are... A parallel-plate capacitor is made from two plates 12.0cm on each side and 4.50mm apart. Half of the... An air-filled parallel plate capacitor has a plate separation of 0.6 cm, and an area 179 mm2. In... A parallel plate air capacitor of capacitance 245pF has a charge of magnitude 0.148ìC on each plate.... A parallel-plate capacitor is designed so that the plates can be pulled apart. The capacitor is init... A parallel plate capacitor has square plates of side L= 12 cm and a distance d= 2 cm between the pla... A square parallel plate capacitor in a circuit with a 2.0 V battery is replaced with a new one. If t...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use