Since the force is given by
F = (constant)*M1*M2/R^2 ,
The new force, after the changes, will be higher by a factor (1.6)^2/(0.5)^2 = 10.24
That means there is a 924% increase.
You do not have to know the actual masses and distances to make that conclusion.
M1 and M2 are the two masses, and R is the distance between them.
If both masses are increased by 60% and the distance between them is halved, by what percent will the force of attraction increase?
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1 answer