Asked by nam maurer

Water is leaving a hose at 6.8 m/s. If the target is 2 m away horizontally, What angle should the water have initially?

Answers

Answered by drwls
Require that the range,
R = Vo^2*sin(2A)/g = 2.0 m

Solve for the angle A. There will be two possible answers.
Answered by Marian
Water
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