Asked by nam maurer

Water is leaving a hose at 6.8 m/s. If the target is 2 m away horizontally, What angle should the water have initially?

13 years ago

Answered by drwls

Require that the range,
R = Vo^2*sin(2A)/g = 2.0 m

Solve for the angle A. There will be two possible answers.

13 years ago

Answered by Marian

Water

6 years ago

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