Asked by rahul patel
newton’s law of gravitation states that any two bodies attract each other with a force that is inversely proportional to the square of the distance between them. The force of attraction between two bodies is 460 * 10^-12 newtons when they are 6 cm apart. What is the force on the bodies when they are 23 cm apart?
Answers
Answered by
Steve
Since the force is k/r^2
Then if r is multiplied by a factor of a, the new force is
k/(ar)^2 = k/r^2 / a^2
So, you have multiplied the distance r by a factor of 23/6. Consequently, the force is reduced by a factor of (23/6)^2.
Then if r is multiplied by a factor of a, the new force is
k/(ar)^2 = k/r^2 / a^2
So, you have multiplied the distance r by a factor of 23/6. Consequently, the force is reduced by a factor of (23/6)^2.
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