Question
An equation of the line in slope intercept form that passes through the point (-9, -1) and is perpendicular to the line y = 3x + 17?
Please help...
Please help...
Answers
Steve
the slope you want is -1/3
Now you have a point and a slope:
(y- (-1))/(x - (-9)) = -1/3
or
(y+1)/(x+9) = -1/3
y+1 = -1/3 x - 3
y = -1/3 x - 4
or
x + 3y + 12 = 0
Now you have a point and a slope:
(y- (-1))/(x - (-9)) = -1/3
or
(y+1)/(x+9) = -1/3
y+1 = -1/3 x - 3
y = -1/3 x - 4
or
x + 3y + 12 = 0